Optimal. Leaf size=149 \[ \frac{(f+g x)^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{4 g}-\frac{b n x (e f-d g)^3}{4 e^3}-\frac{b n (f+g x)^2 (e f-d g)^2}{8 e^2 g}-\frac{b n (e f-d g)^4 \log (d+e x)}{4 e^4 g}-\frac{b n (f+g x)^3 (e f-d g)}{12 e g}-\frac{b n (f+g x)^4}{16 g} \]
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Rubi [A] time = 0.0696452, antiderivative size = 149, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {2395, 43} \[ \frac{(f+g x)^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{4 g}-\frac{b n x (e f-d g)^3}{4 e^3}-\frac{b n (f+g x)^2 (e f-d g)^2}{8 e^2 g}-\frac{b n (e f-d g)^4 \log (d+e x)}{4 e^4 g}-\frac{b n (f+g x)^3 (e f-d g)}{12 e g}-\frac{b n (f+g x)^4}{16 g} \]
Antiderivative was successfully verified.
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Rule 2395
Rule 43
Rubi steps
\begin{align*} \int (f+g x)^3 \left (a+b \log \left (c (d+e x)^n\right )\right ) \, dx &=\frac{(f+g x)^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{4 g}-\frac{(b e n) \int \frac{(f+g x)^4}{d+e x} \, dx}{4 g}\\ &=\frac{(f+g x)^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{4 g}-\frac{(b e n) \int \left (\frac{g (e f-d g)^3}{e^4}+\frac{(e f-d g)^4}{e^4 (d+e x)}+\frac{g (e f-d g)^2 (f+g x)}{e^3}+\frac{g (e f-d g) (f+g x)^2}{e^2}+\frac{g (f+g x)^3}{e}\right ) \, dx}{4 g}\\ &=-\frac{b (e f-d g)^3 n x}{4 e^3}-\frac{b (e f-d g)^2 n (f+g x)^2}{8 e^2 g}-\frac{b (e f-d g) n (f+g x)^3}{12 e g}-\frac{b n (f+g x)^4}{16 g}-\frac{b (e f-d g)^4 n \log (d+e x)}{4 e^4 g}+\frac{(f+g x)^4 \left (a+b \log \left (c (d+e x)^n\right )\right )}{4 g}\\ \end{align*}
Mathematica [A] time = 0.221011, size = 226, normalized size = 1.52 \[ \frac{e x \left (12 a e^3 \left (6 f^2 g x+4 f^3+4 f g^2 x^2+g^3 x^3\right )-b n \left (6 d^2 e g^2 (8 f+g x)-12 d^3 g^3-4 d e^2 g \left (18 f^2+6 f g x+g^2 x^2\right )+e^3 \left (36 f^2 g x+48 f^3+16 f g^2 x^2+3 g^3 x^3\right )\right )\right )+12 b e^3 \left (4 d f^3+e x \left (6 f^2 g x+4 f^3+4 f g^2 x^2+g^3 x^3\right )\right ) \log \left (c (d+e x)^n\right )-12 b d^2 g n \left (d^2 g^2-4 d e f g+6 e^2 f^2\right ) \log (d+e x)}{48 e^4} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.508, size = 836, normalized size = 5.6 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.20284, size = 383, normalized size = 2.57 \begin{align*} \frac{1}{4} \, b g^{3} x^{4} \log \left ({\left (e x + d\right )}^{n} c\right ) + \frac{1}{4} \, a g^{3} x^{4} + b f g^{2} x^{3} \log \left ({\left (e x + d\right )}^{n} c\right ) + a f g^{2} x^{3} - b e f^{3} n{\left (\frac{x}{e} - \frac{d \log \left (e x + d\right )}{e^{2}}\right )} - \frac{1}{48} \, b e g^{3} n{\left (\frac{12 \, d^{4} \log \left (e x + d\right )}{e^{5}} + \frac{3 \, e^{3} x^{4} - 4 \, d e^{2} x^{3} + 6 \, d^{2} e x^{2} - 12 \, d^{3} x}{e^{4}}\right )} + \frac{1}{6} \, b e f g^{2} n{\left (\frac{6 \, d^{3} \log \left (e x + d\right )}{e^{4}} - \frac{2 \, e^{2} x^{3} - 3 \, d e x^{2} + 6 \, d^{2} x}{e^{3}}\right )} - \frac{3}{4} \, b e f^{2} g n{\left (\frac{2 \, d^{2} \log \left (e x + d\right )}{e^{3}} + \frac{e x^{2} - 2 \, d x}{e^{2}}\right )} + \frac{3}{2} \, b f^{2} g x^{2} \log \left ({\left (e x + d\right )}^{n} c\right ) + \frac{3}{2} \, a f^{2} g x^{2} + b f^{3} x \log \left ({\left (e x + d\right )}^{n} c\right ) + a f^{3} x \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.01764, size = 713, normalized size = 4.79 \begin{align*} -\frac{3 \,{\left (b e^{4} g^{3} n - 4 \, a e^{4} g^{3}\right )} x^{4} - 4 \,{\left (12 \, a e^{4} f g^{2} -{\left (4 \, b e^{4} f g^{2} - b d e^{3} g^{3}\right )} n\right )} x^{3} - 6 \,{\left (12 \, a e^{4} f^{2} g -{\left (6 \, b e^{4} f^{2} g - 4 \, b d e^{3} f g^{2} + b d^{2} e^{2} g^{3}\right )} n\right )} x^{2} - 12 \,{\left (4 \, a e^{4} f^{3} -{\left (4 \, b e^{4} f^{3} - 6 \, b d e^{3} f^{2} g + 4 \, b d^{2} e^{2} f g^{2} - b d^{3} e g^{3}\right )} n\right )} x - 12 \,{\left (b e^{4} g^{3} n x^{4} + 4 \, b e^{4} f g^{2} n x^{3} + 6 \, b e^{4} f^{2} g n x^{2} + 4 \, b e^{4} f^{3} n x +{\left (4 \, b d e^{3} f^{3} - 6 \, b d^{2} e^{2} f^{2} g + 4 \, b d^{3} e f g^{2} - b d^{4} g^{3}\right )} n\right )} \log \left (e x + d\right ) - 12 \,{\left (b e^{4} g^{3} x^{4} + 4 \, b e^{4} f g^{2} x^{3} + 6 \, b e^{4} f^{2} g x^{2} + 4 \, b e^{4} f^{3} x\right )} \log \left (c\right )}{48 \, e^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 8.4976, size = 450, normalized size = 3.02 \begin{align*} \begin{cases} a f^{3} x + \frac{3 a f^{2} g x^{2}}{2} + a f g^{2} x^{3} + \frac{a g^{3} x^{4}}{4} - \frac{b d^{4} g^{3} n \log{\left (d + e x \right )}}{4 e^{4}} + \frac{b d^{3} f g^{2} n \log{\left (d + e x \right )}}{e^{3}} + \frac{b d^{3} g^{3} n x}{4 e^{3}} - \frac{3 b d^{2} f^{2} g n \log{\left (d + e x \right )}}{2 e^{2}} - \frac{b d^{2} f g^{2} n x}{e^{2}} - \frac{b d^{2} g^{3} n x^{2}}{8 e^{2}} + \frac{b d f^{3} n \log{\left (d + e x \right )}}{e} + \frac{3 b d f^{2} g n x}{2 e} + \frac{b d f g^{2} n x^{2}}{2 e} + \frac{b d g^{3} n x^{3}}{12 e} + b f^{3} n x \log{\left (d + e x \right )} - b f^{3} n x + b f^{3} x \log{\left (c \right )} + \frac{3 b f^{2} g n x^{2} \log{\left (d + e x \right )}}{2} - \frac{3 b f^{2} g n x^{2}}{4} + \frac{3 b f^{2} g x^{2} \log{\left (c \right )}}{2} + b f g^{2} n x^{3} \log{\left (d + e x \right )} - \frac{b f g^{2} n x^{3}}{3} + b f g^{2} x^{3} \log{\left (c \right )} + \frac{b g^{3} n x^{4} \log{\left (d + e x \right )}}{4} - \frac{b g^{3} n x^{4}}{16} + \frac{b g^{3} x^{4} \log{\left (c \right )}}{4} & \text{for}\: e \neq 0 \\\left (a + b \log{\left (c d^{n} \right )}\right ) \left (f^{3} x + \frac{3 f^{2} g x^{2}}{2} + f g^{2} x^{3} + \frac{g^{3} x^{4}}{4}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.34219, size = 1053, normalized size = 7.07 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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